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(lim)(x->0)(a x+xcosx)/(bsinx)...

`(lim)_(x->0)(a x+xcosx)/(bsinx)`

Text Solution

Verified by Experts

The correct Answer is:
`(a)/(b)lim_(xrarr0)(x)/(sinx)+(1)/(b)lim_(xrarr0)(x)/(sinx)`
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