Home
Class 12
MATHS
The slope of normal to the curve y= sin^...

The slope of normal to the curve `y= sin^(2)x and x= (pi)/(4)` is

A

1

B

`-1`

C

0

D

4

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • SELF ASSESSMENT PAPER 03

    ICSE|Exercise Section-B|10 Videos

  • SELF ASSESSMENT PAPER 03

    ICSE|Exercise Section -C|10 Videos

  • SELF ASSEMENT PAPER 8

    ICSE|Exercise SECTION C|10 Videos

  • SELF ASSESSMENT PAPER 04

    ICSE|Exercise SECTION .C.|12 Videos

Similar Questions

Explore conceptually related problems

Find the slope of the normal to the curve y= cos^(2) x at x = (pi)/(4)

The slope of the normal to the curve y=2x^(2)+3 sin x at x = 0 is

The slope of the normal to the curve y=2x^2+3 sin x at x = 0 is(A) 3 (B) 1/3 (C) -3 (D) -1/3

Find the slope of the normal to the curve x = a sin^(3)t, y = b cos^(3)t at point where t = (pi)/(2) .

The slope of the tangent to the curve y=ln(cosx)" at "x=(3pi)/(4)" is "

Find the slope of the normal to the curve y^(2)=4 ax at ((a)/(m^(2)),(2a)/(m))

Find the slope of the normal to the curve x = a cos^(3) theta, y = a sin^(3) theta at theta = (pi)/(4) . A) 0 B) -1 C) 1 D) none of these

The slope of the tangent to the curve y=sin^(-1) (sin x) " at " x=(3pi)/(4) is

If m denotes the slope of the normal to the curve y= -3 log(9+x^(2)) at the point x ne 0 , then,

The slope of normal to the curve x^(3)=8a^(2)y, a gt 0 at a point in the first quadrant is -(2)/(3) , then point is