`f (x) = (x ^(2) - 9)/(x -3) ` is not defined at `x =3.` What value should be assigned to f(3) for continuity of f (x) at `x =3?`

f(x)=2x+3 if x 2 check continuity of f(x) at x =2.

If f(x) = (x^(2)-9)/(x-3) , find it Lim_(x to 3) f(x) exists .

The function f(x)=(x^3+x^2-16 x+20)/(x-2) is not defined for x=2. In order to make f(x) continuous at x=2,f(2) should be defined as 0 (b) 1 (c) 2 (d) 3

The function f(x)=(x^3+x^2-16 x+20)/(x-2) is not defined for x=2. In order to make f(x) continuous at x=2,f(2) should be defined as 0 (b) 1 (c) 2 (d) 3

If f(x) = (x + 1)/(x-1) , then the value of f{f(3)} is :

Discuss the continuity of f(x)=sgn(x^2-2x+3)

If f(x)=x^(3)-(1)/(x^(3)) , then find the value of f(x)+f(-x) .

The graph of f(x) = (x-3)/(x^(2) - 2x - 3) is shown below. What is the domain of f(x) ?

If f(x) f(x) ={((x^2-9)/(x-3)","" " xne3),(" 6""," " "x = 3"):} then show that f(x) is continuous at x=3.

f(x)=(x+3)/2 For the function f defined above, what is the value of f (−1) ?