(b) The surface area of a soap- bubble is `2.0xx10^(-3) m^(2)` . How much work will be done in blowing the bubble to twice its surface area . `("S.T" =3xx10^(-2)N//m)`

The surface tension of a soap solution is 30 xx 10^(-3) N m^(-1) . How much work is done to increase the radius of a soap bubble from 1.5 cm to 3 cm?

The surface tension of a soap solution is 30 xx 10^(-3) N m^(-1) . How much work is done to increase the radius of a soap bubble from 2 cm to 3 cm?

The amount of work done in forming a soap bubble of radius r = 1 cm (surface tension T = 3 xx 10^(-2) N//m ) is

The surface tension of soap solution is 0.03 N//m . The work done in blowing to from a soap bublle of surface area 40 cm^(2) , (in J) , is

How much work will be done in increasing the diameter of a soap bubble from 2cm to 5cm? Surface tension solution is 3.0xx10^(-2)N//m.

The surface tension of a soap solution is 2xx10^(-2) N//m . To blow a bubble of radius 1cm, the work done is

The work done in blowing a soap bubble of volume V is W . The work done in blowing a soap bubble of volume 2V is

2.0 g of charcoal is placed in 100 mL of 0.05 M CH_(3)COOH to form an adsorbed mono-acidic layer of acetic acid molecules and thereby the molarity of CH_(3)COOH reduces to 0.49 . The surface area of charcoal is 3xx10^(2) m^(2)g^(-1) . The surface area of charcoal is adsorbed by each molecule of acetic acid is a. 1.0xx10^(-18)m^(2) b. 1.0xx10^(-19)m^(2) c. 1.0xx10^(13)m^(2) d. 1.0xx10^(-22)m

The work done in blowing a soap bubble of 10 cm radius is (Surface tension of the soap solution is 3/100 N/m)

The work done in blowing a soap bubble of 10 cm radius is (Surface tension of the soap solution is 3/100 N/m)