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(b) A stone is thrown from a bridge at a...

(b) A stone is thrown from a bridge at an angle of `30^(@)` down with the horizontal with a velocity of `25` m//s . If the stone strikes the water after `2.5` seconds then calculate the height of the bridge from the water surface `(g=9.8 m//s^(2))`.

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To solve the problem of finding the height of the bridge from which the stone is thrown, we can follow these steps: ### Step 1: Break down the initial velocity into components The stone is thrown at an angle of \(30^\circ\) with a velocity of \(25 \, \text{m/s}\). We need to find the vertical component of the velocity, which will affect the height. - The vertical component \(u_y\) can be calculated using: \[ u_y = u \sin(\theta) = 25 \sin(30^\circ) ...
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