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(a) Taking equation of a palne progressi...

(a) Taking equation of a palne progressive wave as `y=alphasin.(2pi)/(gamma)(vt-x)`. Write down the expression for the paticle velocity. Show that the particle veloity at a point = `"wave velocity" xx "slope of the displacement curve at the point"`.

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To solve the problem step by step, we will derive the expression for particle velocity from the given wave equation and then show the relationship between particle velocity, wave velocity, and the slope of the displacement curve. ### Step 1: Write down the wave equation The equation of the plane progressive wave is given as: \[ y = \alpha \sin\left(\frac{2\pi}{\gamma}(vt - x)\right) \] ### Step 2: Find the particle velocity The particle velocity \( v_p \) is defined as the rate of change of displacement \( y \) with respect to time \( t \). Therefore, we differentiate \( y \) with respect to \( t \): ...
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Knowledge Check

  • A transverse wave is represented by the equation y = y_(0) sin (2pi)/(lambda) (vt-x) For what value of lambda is the particle velocity equal to two time the wave velocity ?

    A
    `lambda = 2pi y_(0)`
    B
    `lambda = 2pi y_(0)//3`
    C
    `lambda = piy_(0)//2`
    D
    `lambda = piy_(0)`
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