If the earth were a perfect sphere of radius `6.37 xx 10^(6) m`, rotating about its axis with a period of 1 day `( = 8.64 xx 10^(6) s)`, how much would the acceleration due to gravity differ from the poles to the equator.

Explanation

Use the formula : `g.=g-R_(e)omega^(2)cos^(2)lambda`
at pole `lambda=90^(@)` and at equator `lambda=0^(@)`