A particle of mass m is revolving in a horizontal circle of radius r under a centripetal force `k//r^(2)` where k is a constant. What is the total energy of the particle ?

Explanation

To find the total energy of a particle of mass \( m \) revolving in a horizontal circle of radius \( r \) under a centripetal force given by \( \frac{k}{r^2} \), we will follow these steps:

### Step 1: Understand the Forces Acting on the Particle
The centripetal force \( F_c \) required to keep the particle moving in a circle is provided by the force \( \frac{k}{r^2} \). According to the centripetal force formula:
\[ F_c = \frac{mv^2}{r} \]
Setting these equal gives us:
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