Home
Class 11
PHYSICS
A particle of mass m(o) moves with a spe...

A particle of mass `m_(o)` moves with a speed `C/(2)`. Calculate its mass, momentum, total energy and kinetic energy.

Text Solution

AI Generated Solution

To solve the problem step by step, we will calculate the mass, momentum, total energy, and kinetic energy of a particle of mass \( m_0 \) moving with a speed of \( \frac{c}{2} \). ### Step 1: Calculate the relativistic mass The relativistic mass \( m \) can be calculated using the formula: \[ m = \frac{m_0}{\sqrt{1 - \frac{v^2}{c^2}}} ...
Promotional Banner

Topper's Solved these Questions

  • SELF ASSESSMENT PAPER 5

    ICSE|Exercise Section-C|9 Videos
  • SELF ASSESSMENT PAPER 4

    ICSE|Exercise Section-D|6 Videos
  • THERMAL CONDUCTION

    ICSE|Exercise SELECTED PROBLEMS (Taken from the Previous Years ISC, AISSCE, HSSCE various States. Boards Roorke Qns & NCERT text) FROM EXPERIMENT TO DETERMINE K|2 Videos

Similar Questions

Explore conceptually related problems

A particle of mass m has momentum p. Its kinetic energy will be

A particle of mass m1 is moving with a velocity v_(1) and another particle of mass m_(2) is moving with a velocity v2. Both of them have the same momentum but their different kinetic energies are E1 and E2 respectively. If m_(1) gt m_(2) then

A particle of mass 1kg is moving about a circle of radius 1m with a speed of 1m//s . Calculate the angular momentum of the particle.

A particle of mass 1kg is moving about a circle of radius 1m with a speed of 1m//s . Calculate the angular momentum of the particle.

A rod of mass m spins with an angular speed omega=sqrt(g/l) , Find its a. kinetic energy of rotation. b. kinetic energy of translation c. total kinetic energy.

A particle of mass m and charge q is placed at rest in a uniform electric field E and then released, the kinetic energy attained by the particle after moving a distance y will be

A particle of mass m has half the kinetic energy of another particle of mass m/2 . If the speed of the heavier particle is increased by 2 ms^(-1) its new kinetic energy becomes equal to t he original kinetic energy of the lighter particle. The ratio of the orighinal speeds of the lighter and heavier particle is

The kinetic energy of a particle of mass m moving with speed v is given by K=(1)/(2)mv^(2) . If the kinetic energy of a particle moving along x-axis varies with x as K(x)=9-x^(2) , then The region in which particle lies is :

A particle of mass m moves along line PC with velocity v as shown. What is the angular momentum of the particle about O ?

Two particles A and B of mass 3kg and 2kg moving with speed 10m//s and 5m//s as shown in figure. Kinetic energy of particle A when particle B has the maximum momentum