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A car is moving on a circular path and t...

A car is moving on a circular path and takes a turn. If `R_(1)` and `R_(2)` be the reactions on the inner and outer wheels respectively, then

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Reaction on inner wheel
`R_(1)=(1)/(2)M[g-(v^(2)h)/(ra)]`
Reaction on outer wheel `R_(2)=(1)/(2)[g+(v^(2)h)/(ra)]`
where, r = radius of circular path, 2a = distance between two wheels and h = height of centre of gravity of car.
Therefore `R_(1)ltR_(2)`
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