Home
Class 11
PHYSICS
A force of 100 N is applied horizontally...

A force of 100 N is applied horizontally on a block of mass 10 kg placed on a horizontal floor of coefficient of friction 0.5, The acceleration of the block is `("take" g = 10 ms^(-2))`

A

Zero

B

`5.2 ms^(-2)`

C

`10 ms^(-2)`

D

`5 ms^(-2)`

Text Solution

AI Generated Solution

Promotional Banner

Topper's Solved these Questions

  • SELF ASSESSMENT PAPER 02

    ICSE|Exercise SECTION - A(Answer the following ) |7 Videos
  • SELF ASSESSMENT PAPER 02

    ICSE|Exercise SECTION-B (Answer the following ) |13 Videos
  • SELF ASSESSMENT PAPER 01

    ICSE|Exercise SECION- D (Answer the following ) |6 Videos
  • SELF ASSESSMENT PAPER 3

    ICSE|Exercise Section-D|6 Videos

Similar Questions

Explore conceptually related problems

A block of mass 20 kg is on a horizontal plane of a coefficient of friction 0.5. by applying 6.0 newton force on it, frictional force will be (g = 10m//s^(2)) .

A force of 49 N just able to move a block of wood weighing 10 kg on a rough horizontal surface , then coefficient of friction is

A force of 10N is acting on a block of 20kg on horizontal surface with coefficient of friction mu=0.2 . Calculate the work done by the force.

A block B is pulled by a force of 18 N applied to a light pulley as shown in the figure. If the coefficient of friction is 0.4 and the acceleration of the block is 0.5 ms^(-2) , the mass of the block is (g = 10 m//s^2)

What is the value of applied force ‘F’ which is exerted at an angle theta with the horizontal on a block of mass ‘m’ placed on a horizontal rough surface, if the coefficient of static friction between the block and the surface is , such that the block is on the verge of moving horizontally?

A force F is acting at an angle theta with horizontal on a block of mass 12 kg placed on a rough 3 horizontal surface having coefficient of friction mu=3/ 4 as shown in the figure. The minimum value of force F to just move the block will be (g = 10 ms^-2)

A force F is applied on a block of mass sqrt(3) kg which rests on a horizontal surface with a coefficient of friction 1/(2sqrt3) . The maximum value of F for which the block doesn't move, is [Take g = 10 ms^(-2)]

A block of mass 20kg is pushed with a horizontal force of 90N. If the coefficient of static & kinetic friction are 0.4 & 0.3, the frictional force acting on the block is: (g =10ms^(-2) )

A force F is acting at an angle theta with horizontal on a block of mass 12 kg placed on a rough horizontal surface having coefficient of friction mu=frac{3}{4} as shown in the figure. The minimum value of force F to just move the block will be ( g = 10 ms^-2 )

A block of mass 5 kg is placed on a rough horizontal plane . The coefficients of stastic and kinetic friction between the block and surface are 0*5 and 0*3 respectively. A force of 100 N is applied at an angle 30^(@) with the horizontal as shown in the figure . The acceleration of the block will be [ g = 10 m//s^(2) ]