In a L-C-R circuit, all components connected in series, the emf and the current flowing in the circuit are given by the following equations.
`E=200sin(314t+(pi)/(6))V,1=5sin314tA`
Obtain
(i) the peak values of current and emf.
(ii) the frequency of the AC source.
(iii) the phase difference between current and emf.

Explanation

To solve the problem step by step, we will analyze the given equations for the EMF and current in the L-C-R circuit.

### Given:
1. EMF: \( E = 200 \sin(314t + \frac{\pi}{6}) \, \text{V} \)
2. Current: \( I = 5 \sin(314t) \, \text{A} \)

### Step 1: Obtain the peak values of current and EMF.
The peak value of EMF (\(E_0\)) and the peak value of current (\(I_0\)) can be directly obtained from the equations.
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