Obtain the formula `I=Ktheta` for a moving coil galvanometer, given the deflecting torque `vec(tau)=vec(m)xxvec(B)` where m is the magnetic dipole moment of the coil placed in the magnetic field B, I is the current in the galvanometer and `theta` is the direction.

If in a moving coil galvanometer, a current I produces a deflection theta , then

In a moving coil galvanometer, the deflection of the coil q is related to the electrical current i by the relation

A bar magnet of magnetic moment vec(M) is placed in a magnetic field of induction vec(B) . The torque exerted on it is

If plane of coil and uniform magnetic field B(4T0 is same then torque on the current carrying coil is

Two coils are having magnetic field B and 2B at their centres and current i and 2i then the ratio of their radius is

A magnetic dipole with magnetic moment M is placed at right angles to a magnetic field B. If it is rotated by an angle of 180^(@) , the total work done is

In a moving coil galvanometer a radial magnetic field is obtained with concave magnetic poles, to have

A moving coil galvanometer coil has a coil of area A, number of turns N. The radial magnetic field present is B. the moment of inertia of the coil is I about its rotation axis. The torque is applied by the magnetic field on the coil of the galvanometer when current I_(0) passes through it and produces a deflection of pi//2 of the pointer. Then answer the following questions based on the paragraph. Then the value of torsionl constant of the spring is

A moving coil galvanometer has a 50-turn coil of size 2cm xx 2cm . It is suspended between the magnetic poles producing a magnetic field of 0.5 T . Find the torque on the coil due to the magnetic field when a current of 20mA passes through it.

A moving coil galvanometer has N numbr of turns in a coil of effective area A , it carries a current I . The magnetic field B is radial. The torque acting on the coil is