With the help of a neatly drawn labelled diagram, prove that the magnitude of motional emf .e. is given by e=Blv, where .I. is the length of a metallic rod and `v` is the velocity with which it is pulled in a transverse magnetic field .B..

An electron is moving on a circular path of radius r with speed v in a transverse magnetic field B. e/m for it will be

Current i is carried in a wire of length L . If the wire is turned into a circular coil, the maximum magnitude of torque in a given magnetic field B will be

A glass rod of length l moves with velocity v in a uniform magnetic field B. What is the e.m.f induced in the rod?

A small conducting rod of length l, moves with a uniform velocity v in a uniform magnetic field B as shown in fig __

A wire of length l carries a current I along the x-asis. A magnetic field exists which is given as vecB=B_0(veci+vecj+veck) T. find the magnitude of the magnetic force acting on the wire.

In Thomson.s experiment, prove that the ratio of charge to the mass (e/m) of an electron is given by : (e)/(m)=(1)/(2V).(E^(2))/(B^(2)) where the terms have their usual meaning.

A conducting movable rod AB lies across the frictionless parallel conducting rails in a uniform magnetic field vecB whose magnitude at t=0 is B_(0) . The rod AB is given velocity v right ward and it continues to move with same velocity through out the motion [The acceleration due to gravity is along negative z- axis, i.e. vecg=10m//s^(2)(-hatk) , mass of rod =m .] Which of the following graphs will be the best representation of magnitude of magnetic field versus time.

A metallic V shaped rod OAC is rotated with respect to one of its end in uniform magnetic field, such that axis of rotation is parallel to the direction of magnetic field. Length of each arm of rod is L and angle between the arms is 60^(@) . P is the mid-point of section AC . Magnitude of magnetic field is B . Then choose the correct relation:

A metallic V shaped rod OAC is rotated with respect to one of its end in uniform magnetic field, such that axis of rotation is parallel to the direction of magnetic field. Length of each arm of rod is L and angle between the arms is 60^(@) . P is the mid-point of section AC . Magnitude of magnetic field is B . Then choose the correct relation:

A conducting rod of length l slides at constant velocity v on two parallel conducting rails, placed in a uniform and constant magnetic field B perpendicular to the plane of the rails as shown in Fig.3.49. A resistance R is connected between the two ends of the rails. (a) Idenify the cause which produces change in magnetic flux. (b) Identify the direction of current in the loop. ( c) Determine the emf induced in the loop. (d) Compute the electric power dissipated in the resistor. (e) Calcualte the mechenical power required to pull the rod at a cinstant velovity.