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Electrons having a velocity vecv of 2xx1...

Electrons having a velocity `vecv` of `2xx10^(6)ms^(-1)` pass undeviated through a uniform electric field `vecE` of intensity `5xx10^(4)Vm^(-1)` and a uniform magnetic field `vecB`.
(i) Find the magnitude of magnetic flux density B of the magnetic field.
(ii) What is the direction of `vecB`, if `vecv` is towards right and `vecE` is vertically downwards in the plane of this paper ?

Text Solution

Verified by Experts

Use the relative `v=(E )/(B)` then calculate B.
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