A metallic wire having a resistance of `20Omega` is bent in order to form a complete circle. Calculate the resistance between any two diametrically opposite points on the circle.

A wire of resistance 20 Omega is bent to form a complete circle. The resistance between two diametrically opposite points A and B as shown in the figure, is

A wire of resistance 10(Omega) is bent to form a complete circle.Find its resistance between two diametrically opposite points.

A wire of resistance 12 Omega m^(-1) is bent to from a complete circle of radius 10 cm . The resistance between its two diametrically opposite points, A and B as shown in the figure, is

A wire of resistance 12 Omega m^(-1) is bent to from a complete circle of radius 10 cm . The resistance between its two diametrically opposite points, A and B as shown in the figure, is

When a wire of uniform cross-section a , length I and resistance R is bent into a complete circle, resistance between two of diametrically opposite points will be

A wire has resistance 12 Omega . It is bent in the form of a circle. The effective resistance between two points across a diameter is.

A uniform wire of resistance 9 Omega is joined end-to-end to from a circle. Then, the resistance of the circular wire between any two diametrically points is

A uniform metallic wire has a resistance of 18 Omega and is bent into an equiolateral triangle. Then, the resistance between any two vertices of the triangle is :

A uniform wire os resistance 12 Omega is bent to form a circle. Effective resistance across two diametrically opposite points is

A wire has resistance of 24 Omega is bent in the following shape. The effective resistance between A and B is