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Obtain the relation I=I(0) sin (omegat+ ...

Obtain the relation `I=I_(0) sin (omegat+ pi//2) and X_L= 1//omegaC` for capacitor across which an a.c. emf of `e= e_(0)` sin ot is applied as shown in the figure. Draw a phasor diagram showing emf `e_t` current I and their phase difference `phi`.

Text Solution

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From the relation `E=E_(0) sin omega t=q/C, I=(dq)/(dt)," then use "X_(c)=1/(omega C)`
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