Refractive index of the material of concave lens is `mu`. The lens is immersed inb a medium of refractive index `mu_(1)(mu_(1)gtmu)`. A parallel beam of light is incident on the lens. Draw a diagram to show the path of emergent rays.

The refractive index of the material of a concave lens is n . It is immersed in a medium of refractive index n_(1) . A paprallel beam of light is incident on the lens. Trace the path of emerged rays in each of the following cases : (a) n_(1) gt n (b) n_(1) lt n ( c) n_(1) = n .

A transparent cube of side d, made of a material of refractive index mu_(2) , is immersed in a liquid of refractive index mu_(1)(mu_(1)ltmu_(2)) . . A ray is incident on the face AV at an angle theta (shown in the figure). Total internal refraction takes place at point E on the face BC. Then must satisfy:

A transparent cube of side d, made of a material of refractive index mu_(2) , is immersed in a liquid of refractive index mu_(1)(mu_(1)ltmu_(2)) . . A ray is incident on the face AV at an angle theta (shown in the figure). Total internal refraction takes place at point E on the face BC. Then must satisfy:

A double convex lens, lens made of a material of refractive index mu_(1) , is placed inside two liquids or refractive indices mu_(2) and mu_(3) , as shown. mu_(2)gtmu_(1)gtmu_(3) . A wide, parallel beam of light is incident on the lens from the left. The lens will give rise to

A clear transparent glass sphere (mu=1.5) of radius R is immersed in a liquid of refractive index 1.25. A parallel beam of light incident on it will converge to a point. The distance of this point from the center will be

A thin bi-convex lens made out of a material of refractive index mu_(1) is place in a medium of refractive index mu_(2) . A paraxial beam of light, parallel to the principal axis of the lens, is shown in the figure. Based on the ray diagram, we can conclude that

When a lens of power P (in air) made of material of refractive index mu is immersed in liquid of refractive index mu_(0) Then the power of lens is:

A lens made of material of Refractive index mu_(2) is surrounded by a medium of Refractive Index mu_(1) . The focal length f is related as

A lens made of material of Refractive index mu_(2) is surrounded by a medium of Refractive Index mu_(1) . The focal length f is related as

A bi-convex lens is cut from the middle as shown in figure. Refractive index of material of lens is (3)/(2) . Now lens-1 (as shown in figure) is immersed in a liquid of refractive index mu_(0) . By doing so it is observed that its focal length becomes equal to lens-2. What is the value of mu_(0) ?