If light of wavelength `412.5` nm is incident on each of the metals given below, which one will show photoelectric emission and why ?

Explanation

To determine which metals will show photoelectric emission when light of wavelength 412.5 nm is incident on them, we need to follow these steps:

### Step 1: Calculate the energy of the incident photons
The energy of a photon can be calculated using the formula:
\[ E = \frac{hc}{\lambda} \]
where:
- \( E \) is the energy of the photon,
- \( h \) is Planck's constant (\( 6.626 \times 10^{-34} \, \text{Js} \)),
...