de Broglie wavelength of a moving particle is `lambda`. Its momentum is given by :

Options

A. `(h lambda)/(c)`
B. `(h)/(lambda)`
C. `(hc)/(lambda)`
D. zero

Explanation

To solve the problem, we will use the de Broglie wavelength formula. The de Broglie wavelength (\( \lambda \)) of a moving particle is related to its momentum (\( p \)) by the equation:

\[ \lambda = \frac{h}{p} \]

where:
- \( \lambda \) is the de Broglie wavelength,
- \( h \) is Planck's constant,
- \( p \) is the momentum of the particle.

### Step-by-Step Solution:

1. **Start with the de Broglie wavelength formula**:
\[ \lambda = \frac{h}{p} \]

2. **Rearranging the formula to find momentum**:
To find the momentum \( p \), we can rearrange the equation:
\[ p = \frac{h}{\lambda} \]

3. **Identify the correct option**:
Now, we can see that the momentum \( p \) is given by the expression \( \frac{h}{\lambda} \). This matches with one of the options provided in the question.

4. **Conclusion**:
Therefore, the momentum of the moving particle is:
\[ p = \frac{h}{\lambda} \]
This corresponds to **Option 2**.