If the horizontal component of earth's magnetic field at this place is `3 xx 10^(-5)` T, calculate the earth's total magnetic field at that place. Angle of dip = `delta= 60^(@)`

Explanation

To calculate the Earth's total magnetic field at a place where the horizontal component is given as \( B_h = 3 \times 10^{-5} \, \text{T} \) and the angle of dip \( \delta = 60^\circ \), we can use the relationship between the horizontal component and the total magnetic field.

### Step-by-Step Solution:

1. **Understand the relationship**: The horizontal component of the Earth's magnetic field (\( B_h \)) is related to the total magnetic field (\( B \)) and the angle of dip (\( \delta \)) by the formula:
\[ B_h = B \cos(\delta) \]
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