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Using kirchhoff.s law of electrical netw...

Using kirchhoff.s law of electrical networks , calculate the currents `l_1 , l_2 and l_3` in the circuit shown below .

Text Solution

Verified by Experts

LOOP AFEBA
`-4I_(1)-2I_(1)+6+1I_(2)-8+1I_(2)=0`
`-6I_(1)+2I_(2)=2`

LOOP BEDCB
`-1I_(2)-1I_(2)+8+2I_(3)+2I_(3)-2=0`
`-2I_(2)+4I_(3)=-6`

LOOP AFDCA
`-2I_(1)-4I_(1)+6+2I_(3)+2I_(3)+2I_(3)-2=0`
`-6I_(1)+4I_(3)=-4`
Solve (i) (ii) ,(iii)
`I_(1)=-(1)/(3)A`

`I_(2)=OA`
`I_(3)=-(-3)/(2)A`
Since the value of currents are negative it shows that the directions marked in the circuit should be reversed .
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