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Calculate angle of minimum deviation (de...

Calculate angle of minimum deviation `(delta_(m))` for a regular glass prism. (Refractive index of glass = 1.6)

Text Solution

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Given, `A=60^(@),n=1.6`
`delta_(m)=?`
We know `n=(sin((A+delta_(m))/(2)))/(sinA//2)`
`1.6=(sin((60+delta_(m))/(2)))/(sin((60)/(2)))`
`sin((60^(@)+delta_(m))/(2))=1.6xx(1)/(2)`
`(60^(@)+delta_(m))/(2)=sin^(-1)(0.8)`
`60^(@)+delta_(m)=106.26^(@)`
`therefore delta_(m)=106.26^(@)-60^(@)=46.26^(@)`
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