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The ratio in which the line segment jo...

The ratio in which the line segment joining the points An(-2,3,6) and B(3,4,-1) is divide by the plane 2x + 3y - z = 3 is

A

1 : 4

B

3 : 4

C

4 : 1

D

4 : 3

Text Solution

AI Generated Solution

The correct Answer is:
To find the ratio in which the line segment joining the points A(-2, 3, 6) and B(3, 4, -1) is divided by the plane 2x + 3y - z = 3, we can follow these steps: ### Step 1: Define the Points and the Plane Let A(-2, 3, 6) and B(3, 4, -1) be the points. The equation of the plane is given as 2x + 3y - z = 3. ### Step 2: Assume the Ratio Assume the line segment AB is divided by the point C in the ratio k:1. The coordinates of point C can be expressed using the section formula as follows: - \( C_x = \frac{k \cdot x_2 + 1 \cdot x_1}{k + 1} \) - \( C_y = \frac{k \cdot y_2 + 1 \cdot y_1}{k + 1} \) - \( C_z = \frac{k \cdot z_2 + 1 \cdot z_1}{k + 1} \) Where \( (x_1, y_1, z_1) = (-2, 3, 6) \) and \( (x_2, y_2, z_2) = (3, 4, -1) \). ### Step 3: Calculate the Coordinates of C Substituting the coordinates of A and B into the formulas: - \( C_x = \frac{k \cdot 3 + 1 \cdot (-2)}{k + 1} = \frac{3k - 2}{k + 1} \) - \( C_y = \frac{k \cdot 4 + 1 \cdot 3}{k + 1} = \frac{4k + 3}{k + 1} \) - \( C_z = \frac{k \cdot (-1) + 1 \cdot 6}{k + 1} = \frac{-k + 6}{k + 1} \) ### Step 4: Substitute C into the Plane Equation Since point C lies on the plane, we substitute \( C_x, C_y, C_z \) into the plane equation: \[ 2C_x + 3C_y - C_z = 3 \] Substituting the values: \[ 2\left(\frac{3k - 2}{k + 1}\right) + 3\left(\frac{4k + 3}{k + 1}\right) - \left(\frac{-k + 6}{k + 1}\right) = 3 \] ### Step 5: Simplify the Equation Multiply through by \( k + 1 \) to eliminate the denominator: \[ 2(3k - 2) + 3(4k + 3) + (k - 6) = 3(k + 1) \] Expanding each term: \[ 6k - 4 + 12k + 9 + k - 6 = 3k + 3 \] Combine like terms: \[ (6k + 12k + k) + (-4 + 9 - 6) = 3k + 3 \] This simplifies to: \[ 19k - 1 = 3k + 3 \] ### Step 6: Solve for k Rearranging gives: \[ 19k - 3k = 3 + 1 \] \[ 16k = 4 \] \[ k = \frac{1}{4} \] ### Step 7: Find the Ratio The ratio in which the line segment is divided is \( k:1 \), which is: \[ \frac{1}{4}:1 \] This can be expressed as: \[ 1:4 \] ### Final Answer The ratio in which the line segment joining the points A and B is divided by the plane is **1:4**. ---
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