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A line segment of length 7.5 cm was wron...

A line segment of length 7.5 cm was wrongly measured as 7.2 cm. What was the error per cent ?

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To solve the problem of finding the error percentage when a line segment of length 7.5 cm is wrongly measured as 7.2 cm, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Original and Measured Lengths**: - Original Length (O) = 7.5 cm - Measured Length (M) = 7.2 cm 2. **Calculate the Error**: - Error (E) = Original Length - Measured Length - E = 7.5 cm - 7.2 cm - E = 0.3 cm 3. **Calculate the Error Percentage**: - The formula for error percentage is: \[ \text{Error Percentage} = \left(\frac{\text{Error}}{\text{Original Length}}\right) \times 100 \] - Substitute the values into the formula: \[ \text{Error Percentage} = \left(\frac{0.3 \text{ cm}}{7.5 \text{ cm}}\right) \times 100 \] 4. **Perform the Calculation**: - First, calculate the fraction: \[ \frac{0.3}{7.5} = 0.04 \] - Now, multiply by 100 to get the percentage: \[ 0.04 \times 100 = 4\% \] 5. **Final Result**: - The error percentage is **4%**.
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