A team won 6 hockey matches and lost 9 matches. What per cent of the matches did the team win ?

Answer

To find the percentage of matches that the team won, we can follow these steps:

### Step 1: Determine the number of matches won and lost.
- The team won 6 matches.
- The team lost 9 matches.

### Step 2: Calculate the total number of matches played.
- Total matches = Matches won + Matches lost
- Total matches = 6 + 9 = 15

### Step 3: Use the formula for percentage.
- The formula for percentage is:
\[ \text{Percentage} = \left( \frac{\text{Number of successes}}{\text{Total number of trials}} \right) \times 100 \]
- Here, the number of successes (matches won) is 6, and the total number of trials (total matches) is 15.

### Step 4: Substitute the values into the formula.
\[ \text{Percentage of matches won} = \left( \frac{6}{15} \right) \times 100 \]

### Step 5: Simplify the fraction.
- To simplify \(\frac{6}{15}\), we can divide both the numerator and the denominator by their greatest common divisor, which is 3:
\[ \frac{6 \div 3}{15 \div 3} = \frac{2}{5} \]

### Step 6: Calculate the percentage.
- Now substitute back into the percentage formula:
\[ \text{Percentage of matches won} = \left( \frac{2}{5} \right) \times 100 \]
- To calculate \(\frac{2}{5} \times 100\):
\[ \frac{2 \times 100}{5} = \frac{200}{5} = 40 \]

### Final Answer:
- The team won **40%** of the matches.

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