Define battery. How are overall emf of battery related to emf of the cells when connected in series ?

Battery is a collection of cells connected in

Twelve cells each having the same e.m.f are connected in series and are kept to a closed box. Some of the cell are connected in reverse order .The battery is connected in series with an ammeter an external resistance R and two cells of the same type as an in the battery .The current when they and support each other is 3 ampere and current is 2 ampare when the two oppose each other. How many cells are connected in reverse order ?

The initial rate of increase of current, when a battery of emf 6 V is connected in series with an inductance of 2 H and resistance 12Omega , is

In the series connection of cells, overall emf of the battery is algebraic ______________ of all individual cells connected in series.

12 cells each having the same emf are connected in series and are kept in a closed box. Some of the cells are wrongly connected. This battery is connected in series with an ammeter and two similar cells . The current is 3A when the two cells aid the battery and is 2A when the cells and the battery oppose each other. How many cells in the battery are wrongly connected?

The emf of the battery shown in figure is

Draw a circuit diagram when three bulbs are connected in series with a battery of cells, which are also connected in series.

Twelve cells each having the same emf are connected in series and are kept in a closed box. Some of the cells are wrongly connected. This battery of cells is connected in series with an ammeter and two cells identical with the others. The current is 3A when the cells and the battery aid each other and is 2A when the cells and the battery oppose each other. How many cells in the batter are wrongly connected?

n. cells, each of emf .e. and internal resistance .r. are joined in series to form a row. .m. such rows are connected in parallel to form a battery of N = mn cells. This battery is connected to an external resistance .R.. (i) What is the emf of this battery and how much is its internal resistance ? Show that current .l. flowing through the external resistance .R. is given by- I=(Ne)/(mR+nr)

find the emf of the battery shown in figure below: