Calculate the potential for half-cell containing 0.10 `MK_(2)Cr_(2)O_(7)(aq),0.20M Cr^(3+)(aq) and 1.0xx10^(-4)MH^(+)(aq)`. The half-cell reaction is
`Cr_(2) O_(7)^(2-)(aq) +14H^(+) +6e^(-) to 2Cr^(3+)(aq) +7H_(2)O(l)`

Explanation

To calculate the potential for the half-cell reaction given, we will use the Nernst equation. The half-cell reaction is:

\[ \text{Cr}_2\text{O}_7^{2-} (aq) + 14 \text{H}^+ + 6 e^- \rightarrow 2 \text{Cr}^{3+} (aq) + 7 \text{H}_2\text{O} (l) \]

### Step-by-Step Solution:

**Step 1: Identify the Nernst Equation**

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