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Calculate the emf of the cell in which t...

Calculate the emf of the cell in which the following reaction takes place :
`Ni(s)+2Ag^(+)(0.002M) to Ni^(2+) (0.160M) +2Ag(s)`
Given that `E_("cell")^(Theta)=1.05V`

Text Solution

Verified by Experts

Using Nernst equation, we have
`E_("cell")=E_("cell")^(Theta)-(0.0591)/(2)"log"([Ni^(2+)])/([Ag^(+)]^(2))`
`=1.05V-0.0295"log"([0.160])/([0.002]^(2))`
`=1.05V-0.0295[log 0.160-2log 0.002]V`
`=1.05V -0.1376 V=0.9124V`
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