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The conductivity of a 0.20 M solution of...

The conductivity of a 0.20 M solution of KCl at 298 K is `0.0248 S cm^(-1)` . Calculate its molar conductivity .

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Molarity of solution, M=0.20
Conductivity, `k = 0.0248 "S cm"^(-1)=2.48 xx 10^(-2)"ohm"^(-1)cm^(-1)`
Molar conductivity, `wedge_(m)=(k xx 1000)/(M)"ohm"^(-1) cm^(2) "mol"^(-1)`
`=(2.48 xx 10^(-2) xx 1000)/(0.20) "ohm"^(-1)cm^(-2)"mol"^(-1)= 124.0S cm^(2)"mol"^(-1)`
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