On electrolysis of an aqueous electrolyte between copper electrodes, it is observed that cuprous oxide (molecular weight 143) is formed at the anode. What will be the weight of the cuprous oxide formed if a current of 0.965 A is passed for 2000 sec ?

Explanation

To find the weight of cuprous oxide (Cu2O) formed during the electrolysis, we can follow these steps:

### Step 1: Understand the Reaction
At the anode, copper is oxidized to cuprous oxide. The half-reaction can be represented as:
\[ 2Cu \rightarrow 2Cu^+ + 2e^- \]
This indicates that 2 moles of copper will produce 1 mole of cuprous oxide (Cu2O).

### Step 2: Calculate the Total Charge (Q)
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