How many coulombs are required for the following reductions?
1 mol of `MnO_(4)^(-) " to "Mn^(2+)`.

Explanation

To determine how many coulombs are required for the reduction of 1 mole of \( \text{MnO}_4^{-} \) to \( \text{Mn}^{2+} \), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the oxidation states**:
- In \( \text{MnO}_4^{-} \), let the oxidation state of manganese (Mn) be \( x \).
- The oxidation state of oxygen (O) is -2. Since there are 4 oxygen atoms, the total contribution from oxygen is \( 4 \times (-2) = -8 \).
- The overall charge of the ion is -1. Therefore, we can set up the equation:
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