The e.m.f `E_("cell")^(Theta)` of the cell reaction `3Sn^(4+) +2Cr to 3Sn^(4+) +2Cr^(3+) ` is 0.89 V. Calculate `Delta_(r )G^(Theta)` for the reaction `(F=96500"C mol"^(-1))`.

Answer

`-515.3kJ`

Explanation

`E_("cell")^(Theta) =0.89V`, For the given cell reaction, we have
`Sn^(4+)+2e^(-) to Sn^(2+)"]"xx3, Cr^(3+) +3e^(-) to Cr"]" xx2`
`:.n=6`
`DeltaG^(Theta)= -nFE_("cell")^(Theta)= -6xx96500 xx 0.89 = -515310J`
`= -515.31 kJ`