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The conductivity of 0.20 M solution of K...

The conductivity of 0.20 M solution of KCl at 298 K is 0.025 S `cm^(-1)`. Calculate its molar conductivity.

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The correct Answer is:
`125.0s cm^(2) "mol"^(-1)`
`k=2.5xx10^(-2)"ohm"^(-1)cm^(-1), M=0.20`
Molar conductivity, `wedge_(m)= (k xx 1000)/(M)"ohm"^(-1)"cm"^(2)"mol"^(-1)`
`=(2.5 xx10^(-2) xx 1000)/(0.20) "ohm"^(-1)cm^(2)"mol"^(-1)`
`=125S cm^(2) "mol"^(-1)`
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