Home
Class 12
CHEMISTRY
The conductivity of 0.01N KCl solution i...

The conductivity of 0.01N KCl solution is 0.0014106 `"ohm"^(-) cm^(-)` at 298 K. When a conductivity cell was filled up with the same solution, it offered a resistance of 484 ohms at 298 K. The same cell was then filled with 0.001 N solution of NaCl at the same temperature which gave a resistance of 5496 ohms. Calculate the value of equivalent conductivity of 0.001 N NaCI solution.

Text Solution

AI Generated Solution

The correct Answer is:
To calculate the equivalent conductivity of a 0.001 N NaCl solution, we will follow these steps: ### Step 1: Calculate the Cell Constant The cell constant (K) can be calculated using the formula: \[ K = \text{Specific Conductance} \times \text{Resistance} \] Given that the specific conductance of the 0.01 N KCl solution is \( 0.0014106 \, \text{ohm}^{-1} \text{cm}^{-1} \) and the resistance is \( 484 \, \text{ohms} \), we can substitute these values into the formula: \[ K = 0.0014106 \, \text{ohm}^{-1} \text{cm}^{-1} \times 484 \, \text{ohms} \] \[ K = 0.683 \, \text{cm}^{-1} \] ### Step 2: Calculate the Specific Conductance of the 0.001 N NaCl Solution Using the cell constant calculated in Step 1, we can find the specific conductance of the 0.001 N NaCl solution. The formula is: \[ \text{Specific Conductance} (k_2) = \frac{K}{R} \] Where \( R \) is the resistance of the NaCl solution, which is \( 5496 \, \text{ohms} \): \[ k_2 = \frac{0.683 \, \text{cm}^{-1}}{5496 \, \text{ohms}} \] \[ k_2 = 0.000124 \, \text{ohm}^{-1} \text{cm}^{-1} \] ### Step 3: Calculate the Equivalent Conductivity The equivalent conductivity (\( \Lambda \)) can be calculated using the formula: \[ \Lambda = \frac{k \times 1000}{N} \] Where: - \( k \) is the specific conductance of the NaCl solution (from Step 2), - \( N \) is the normality of the solution (which is \( 0.001 \, N \)). Substituting the values: \[ \Lambda = \frac{0.000124 \, \text{ohm}^{-1} \text{cm}^{-1} \times 1000}{0.001} \] \[ \Lambda = 124.2 \, \text{ohm}^{-1} \text{cm}^2 \text{g}^{-1} \] ### Final Answer The equivalent conductivity of the 0.001 N NaCl solution is: \[ \Lambda = 124.2 \, \text{ohm}^{-1} \text{cm}^2 \text{g}^{-1} \] ---

To calculate the equivalent conductivity of a 0.001 N NaCl solution, we will follow these steps: ### Step 1: Calculate the Cell Constant The cell constant (K) can be calculated using the formula: \[ K = \text{Specific Conductance} \times \text{Resistance} \] Given that the specific conductance of the 0.01 N KCl solution is \( 0.0014106 \, \text{ohm}^{-1} \text{cm}^{-1} \) and the resistance is \( 484 \, \text{ohms} \), we can substitute these values into the formula: \[ K = 0.0014106 \, \text{ohm}^{-1} \text{cm}^{-1} \times 484 \, \text{ohms} \] ...
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    ICSE|Exercise EXERCISE (PART-I Objective Questions)|28 Videos
  • ELECTROCHEMISTRY

    ICSE|Exercise EXERCISE (PART-I Objective Questions) (Choose the correct alternative) |25 Videos
  • ELECTROCHEMISTRY

    ICSE|Exercise ISC EXAMINATION QUESTIONS (PART-II Numerical Problems) |19 Videos
  • DISTINCTION BETWEEN PAIRS OF COMPOUNDS

    ICSE|Exercise QUESTIONS |155 Videos
  • GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS

    ICSE|Exercise EXERCISE (PART-I ( OBJECTIVE QUESTIONS )) (Fill in the blanks)|60 Videos

Similar Questions

Explore conceptually related problems

If conductivity of 0.1 mol/dm^3 solution of KCl is 1.3 * 10^(-2) S cm^(-1) at 298 K then its molar conductivity will be

Conductivity of 0.01 M NaCl solution is 0.00147" ohm"^(-1) cm^(-1) . What happens to this conductivity if extra 100 ml of H_(2)O is added to the above solution?

The conductivity of 0*2M " KCl solution is " 3 Xx 10^(-2) ohm^(-1) cm^(-1) . Calculate its molar conductance.

The specific conductivity of 0.5N solution is 0.01287 ohm^(-1) cm^(-1) . What would be its equivalent conductance?

The conductivity of 0.20M solution of KCl at 298K is 0.0248 S cm^(-1) . Calculate its molar conductivity.

The conductivity of 0.35M solution of KCl at 300K is 0.0275 S cm^(-1) . Calculate molar conductivity

The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 S cm^(-1) . Calculate its molar conductivity.

The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 S cm^(-1) . Calculate its molar conductivity.

The conductivity of 0.20 M solution of KCl at 298 K is 0.025 S cm^(-1) . Calculate its molar conductivity.

The conductivity of 0.10 M solution of KCl at 298 K is 0.025 S cm Calculate its molar conductivity.

ICSE-ELECTROCHEMISTRY-Follow up Problems
  1. For the chemical equilibrium PCl(5)(g) hArr PCl(3)(g) +Cl(2) (g) " a...

    Text Solution

    |

  2. The resistace of a conductivity cell containing 0.001 M KCl solution a...

    Text Solution

    |

  3. The conductivity of 0.20 M solution of KCl at 298 K is 0.025 S cm^(-1)...

    Text Solution

    |

  4. The resistance of a cell (cell constant = 1.1 cm^(-1)) containing (N)/...

    Text Solution

    |

  5. The conductivity of 0.01N KCl solution is 0.0014106 "ohm"^(-) cm^(-) ...

    Text Solution

    |

  6. 0.5N solution of a salt placed between two Pt electrodes 2.0 cm apart ...

    Text Solution

    |

  7. Conductivity of a solution containing one gram of anhydrous BaCl(2) in...

    Text Solution

    |

  8. The electical resistance of a column of 0.05 M , NaOH solution of diam...

    Text Solution

    |

  9. The resistance of 0.01 M CH(2)COOH solution was found to be 2220 ohm i...

    Text Solution

    |

  10. The molar conductivity of NH(4)Cl at infinite dilution is 149.7"ohm"^(...

    Text Solution

    |

  11. Calculate the value of equivalent conductivity of MgCl(2) at infinite...

    Text Solution

    |

  12. Calculate ^^(m)^(@) for CaCl(2) an MgSO(4) from the data given in tabl...

    Text Solution

    |

  13. The equivalent conductances at infinite dilution of NH(4)Br, KOH and K...

    Text Solution

    |

  14. The molar conductivity of KCl solutions at different concentration at...

    Text Solution

    |

  15. What wil be the products of electrolysis of an aqueous solution of AgN...

    Text Solution

    |

  16. (a) Predict the products of electrolysis in each of the following : ...

    Text Solution

    |

  17. (a) Predict the products of electrolysis in each of the following : ...

    Text Solution

    |

  18. Predict the products of electrolysis in each of the following (i) an...

    Text Solution

    |

  19. What will happen during the electrolysis of aqueous solution of CuSO(4...

    Text Solution

    |

  20. Why potassium cannot be obtained by the electrolysis of an aqueous sol...

    Text Solution

    |