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Calculate ^^(m)^(@) for CaCl(2) an MgSO(...

Calculate `^^_(m)^(@)` for `CaCl_(2)` an `MgSO_(4)` from the data given in table

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The correct Answer is:
`wedge^(0)(CaCl_(2))=271.6 S cm^(2) "mol"^(-1); wedge_(MgSO_(4))^(0)=266 S cm^(2)"mol"^(-1)`

`wedge_(CaCl_(2))^(0)=wedge_(Ca^(2+))^(0) +2wedge_(Cl^(-))^(0) 119.0+2(76.3)`
`=119.0+152.6`
`=271.6" ohm"^(-1)cm^(2)"mol"^(-1)`
`wedge_(MgSO_(4))^(0) =wedge_(Mg^(2+))^(0) +wedge_(SO_(4)^(2-))^(0) =106+160`
`=266" ohm"^(-1) cm^(2)"mol"^(-1)`
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wedge^(@)._(m) for CaCl_(2) and MgSO_(4) from the given data. lambda_(Ca^(2+))^(@)=119.0S cm^(2)mol^(-1) ltbr. lambda_(Cl^(c-))^(@)=76.3S cm^(2)mol^(-1) lambda_(Mg^(2+))^(@)=106.0S cm^(2)mol^(-1) lambda_(SO_(4)^(2-))^(@)=160.0 cm^(2)mol^(-1)

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