Fill in the blanks by choosing the appropriate word/words from those given in the brackets:
(ionic conduction, electronic conduction, anode, cathode, one coulomb, one faraday of their equivalent weights, of their molecular weights, decoration, Avogadro's number, proton number, loss of electrons, gain of electrons, can, cannot, e.m.f., negative, positive, greater, `H_(2)`, sodium, less, more, bad, good, increases, decreases electrode potential, negative, positive, greater, less, `H_(2), O_(2)`, more).
The electrochemical equivalents of the two metals are in the ratio...............

Explanation

To solve the question, we need to fill in the blank with the appropriate words from the options provided. The question states: "The electrochemical equivalents of the two metals are in the ratio..............."

### Step-by-Step Solution:

1. **Understanding Electrochemical Equivalents**: The electrochemical equivalent (E) of a substance refers to the mass of the substance that is deposited or liberated at an electrode during electrolysis when a certain amount of electric charge passes through the electrolyte.

2. **Faraday's Laws of Electrolysis**: According to Faraday's second law of electrolysis, the electrochemical equivalents of different substances are directly proportional to their equivalent weights. This means that if you pass the same amount of electricity through different substances, the amount of substance deposited will depend on their equivalent weights.

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