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The equivalent conductance of Ba^(2+) an...

The equivalent conductance of `Ba^(2+)` and `Cl^-` are respectively 127 and 76 `"ohm"^(-1) cm^2 eq^(-1)` at infinite dilution. What will be the equivalent conductance of `BaCl_2` at infinite dilution ?

A

203

B

279

C

101.5

D

139.5.

Text Solution

Verified by Experts

The correct Answer is:
D
`wedge_(m)^(0) (BaCl_(2))=lambda_(Ba^(2+))^(@) +2(lambda_(Cl^(-))^(@))=127 +2 xx 76 =279 Omega^(-1)cm^(2)"mol"^(-1)`
`wedge_(eq)=(279)/(2)Omega^(-1) cm^(2)"mol"^(-1)=139.5Omega^(-1)cm^(2)eq^(-1)" "[ :. "Z for "BaCl_(2)=2]`
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