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Lambda(m(NH4OH))^@ is equal to...

`Lambda_(m(NH_4OH))^@` is equal to

A

`wedge_(m(NH_(4)OH))^(0) +wedge_(m(NH_(4)Cl))^(0) -wedge_((HCl))^(0)`

B

`wedge_(m(NH_(4)Cl))^(0) +wedge_(m(NaOH))^(0) -wedge_((NaCl))^(0)`

C

`wedge_(m(NH_(4)Cl))^(0) +wedge_(m(NaCl))^(0) -wedge_((NaOH))^(0)`

D

`wedge_(m(NaOH))^(0) +wedge_(m(NaCl))^(0) -wedge_((NH_(4)Cl))^(0)`

Text Solution

Verified by Experts

The correct Answer is:
B
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