How much charge is required for the reduction of 1 mole of `Cu^(2+)` to Cu?

Explanation

To determine how much charge is required for the reduction of 1 mole of \( \text{Cu}^{2+} \) to \( \text{Cu} \), we can follow these steps:

### Step 1: Write the Reduction Reaction
The reduction of copper ions can be represented by the following half-reaction:
\[ \text{Cu}^{2+} + 2 \text{e}^- \rightarrow \text{Cu} \]
This equation shows that 1 mole of \( \text{Cu}^{2+} \) requires 2 moles of electrons for its reduction to metallic copper.
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