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Calculate E("cell") at 25^(@)C for the ...

Calculate `E_("cell")` at `25^(@)C` for the reaction :
`Zn+Cu^(2+) (0.20M) to Zn^(2+) (0.50M)+Cu`
Given `E^(Theta) (Zn^(2+)//Zn)= -0.76V, E^(Theta)(Cu^(2+)//Cu)=0.34V`.

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To calculate the cell potential \( E_{\text{cell}} \) at \( 25^\circ C \) for the given reaction: \[ \text{Zn} + \text{Cu}^{2+} (0.20 \, M) \rightarrow \text{Zn}^{2+} (0.50 \, M) + \text{Cu} \] we will follow these steps: ...
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ICSE-ELECTROCHEMISTRY-ISC EXAMINATION QUESTIONS (PART-II Numerical Problems)
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  2. For the cell : Zn"|"Zn^(2+) (a=1)"||"Cu^(2+) (a=1)"|"Cu Given that ...

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  12. Calculate the value of E("cell") at 298 K for the following cell: ...

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  13. 0*05 " M " NaOH solution offered a resistance of 31*6 ohm in a conduct...

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  14. 0*3605 g of a metal is deposited on the electrode by passing 1*2 amper...

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  15. How many hours does it take to reduce 3 moles of Fe^(3+) to Fe^(2+) wi...

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  17. The specific conductance of a 0.01 M solution of acetic acid at 298 K...

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  18. Calculate the number of coulombs required to deposit 5.4g of Al when ...

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  19. A 0.05 M NH OH solution offers the resistance of 50 ohms to a conduct...

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