Calculate the maximum work that can be obtained from the given electrochemical cell constructed with two metals M and N.
`[E_(M^(2+)//M)^(Theta)= -0.76V, E_(N^(2+)//N)^(Theta) = 0.34V]`

Explanation

To calculate the maximum work that can be obtained from the given electrochemical cell constructed with two metals M and N, we will follow these steps:

### Step 1: Identify the half-reactions and standard electrode potentials.
We are given:
- \( E^\circ_{M^{2+}/M} = -0.76 \, \text{V} \)
- \( E^\circ_{N^{2+}/N} = 0.34 \, \text{V} \)

### Step 2: Determine the anode and cathode.
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