Home
Class 12
CHEMISTRY
0*3605 g of a metal is deposited on the ...

`0*3605` g of a metal is deposited on the electrode by passing `1*2` amperes of current for 15 minutes through its salt solution. The atomic weight of the metal is 96. What is the valency of the metal ?

Text Solution

Verified by Experts

Current passed, `I= 1.2 ` amp
Time for which current is passed = 15 min
`=15xx 60=900s`
Charge (in coulomb) passed through the solution
`= I xx t`
`=1.2 xx 900=1080C`
1080 coulomb deposit metal = 0.3605 g
96500 coulomb deposit metal
`=(0.3605)/(1080) xx 96500 =32.21 g`
`:.` Gram equivalent of metal = 32.21 g
Atomic mass = Eq. mass `xx` Valency
`:.` Valency `=(96)/(32.21)=2.98=3`
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    ICSE|Exercise ISC EXAMINATION QUESTIONS (PART-II Descriptive Questions) |11 Videos

  • DISTINCTION BETWEEN PAIRS OF COMPOUNDS

    ICSE|Exercise QUESTIONS |155 Videos

  • GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS

    ICSE|Exercise EXERCISE (PART-I ( OBJECTIVE QUESTIONS )) (Fill in the blanks)|60 Videos

Similar Questions

Explore conceptually related problems

70 gms of a metal oxide on reduction produced 54 gms of metal. The atomic weight of the metal is 81. What is its valency?

25 gm of a metal is deposited on cathode during the electrolysis of metal nitrate solution by a current of 5 apm pssing for 4 hour if atomic weight of the metal is 100 The valency of metal in metal intrates is

1 mole of OH^(-) ions is obtained from 85 g of hydroxide of a metal. What is the equivalent weight of the metal ?

M^(2+) +2e rarr M. 0.275 g of metal M is deposited at the cathode due to passage of 1A of current for 965s. Hence atomic weight of the metal M is:-

The amount of metal deposited at cathode on passing electric current of 0.75 ampere in aqueous ferrous sulphate solution for 30 minutes, will be. (atomic weight of Fe=56)

A current of 0.65A flowing for 10 minutes, deposit 2.0g of a metal. The equivalent weight of the metal is

A current of 9.65A flowing for 10 minutes deposits 3.0g of the metal which is monovalent. The atomic mass of the metal is

When X amperes of current is passed through molten AlCl_(3) for 96.5 s. 0.09 g of aluminium is deposited. What is the value of X?

How much copper is deposited on the cathode if a current of 3A is passed through aqueous CuSO_(4) solution for 15 minutes?

A current of 9.95 amp following for 10 minutes, deposits 3 gm of a metal. Equivalent weight of the metal is:

ICSE-ELECTROCHEMISTRY-ISC EXAMINATION QUESTIONS (PART-II Numerical Problems)
  1. A cell is constructed by dipping a zinc rod in 0.1 M zinc nitrate solu...

    Text Solution

    |

  2. For the cell : Zn"|"Zn^(2+) (a=1)"||"Cu^(2+) (a=1)"|"Cu Given that ...

    Text Solution

    |

  3. Calculate the equivalent conductivity of 1M H(2)SO(4), whose specific...

    Text Solution

    |

  4. A current of 10 A is passed for 80 min and 27 seconds through a cell ...

    Text Solution

    |

  5. Calculate E("cell") at 25^(@)C for the reaction : Zn+Cu^(2+) (0.2...

    Text Solution

    |

  6. A 0.05 M NaOH solution offered a resistance of 31.6 ohms in a conduct...

    Text Solution

    |

  7. For the following cell, calculate the emf: Al//Al^(3+) (0.01 M)"||"...

    Text Solution

    |

  8. A solution of 0.1 N KCl offers a resistance of 245 ohms. Calculate th...

    Text Solution

    |

  9. How many electrons will flow when a current of 5 amperes is passed thr...

    Text Solution

    |

  10. Consider the reaction 2Ag^(+) +Cd to 2Ag to 2Ag +Cd^(2+). The stan...

    Text Solution

    |

  11. Calculate the maximum work that can be obtained from the given electr...

    Text Solution

    |

  12. Calculate the value of E("cell") at 298 K for the following cell: ...

    Text Solution

    |

  13. 0*05 " M " NaOH solution offered a resistance of 31*6 ohm in a conduct...

    Text Solution

    |

  14. 0*3605 g of a metal is deposited on the electrode by passing 1*2 amper...

    Text Solution

    |

  15. How many hours does it take to reduce 3 moles of Fe^(3+) to Fe^(2+) wi...

    Text Solution

    |

  16. Calculate the emf of the following cell reaction at 298 K: Mg(s) +C...

    Text Solution

    |

  17. The specific conductance of a 0.01 M solution of acetic acid at 298 K...

    Text Solution

    |

  18. Calculate the number of coulombs required to deposit 5.4g of Al when ...

    Text Solution

    |

  19. A 0.05 M NH OH solution offers the resistance of 50 ohms to a conduct...

    Text Solution

    |