Calculate the emf of the following cell reaction at 298 K:
`Mg(s) +Cu^(2+) (0.0001 M) to Mg^(2+) (0.001M) +Cu(s) `
The standard potential `(E^(Theta))` of the cell is 2.71 V.

Explanation

To calculate the emf of the given cell reaction at 298 K, we will use the Nernst equation. The Nernst equation relates the cell potential (emf) to the standard potential and the concentrations of the reactants and products.

### Step-by-Step Solution:

1. **Identify the Reaction and Standard Potential:**
The cell reaction is:
\[
\text{Mg(s)} + \text{Cu}^{2+} (0.0001 \, M) \rightarrow \text{Mg}^{2+} (0.001 \, M) + \text{Cu(s)}
...