A 0.05 M NH OH solution offers the resistance of 50 ohms to a conductivity cell at 298 K. If the cell constant is 0.50 `cm^(-1)` and molar conductance of `NH_(4)OH` at infinite dilution is `471.4 ohm^(-1) cm^(2) "mol"^(-1)` calculate :
(i) Specific conductance
(ii) Molar conductance
(iii) Degree of dissociation.

Explanation

To solve the problem step by step, we will calculate the specific conductance, molar conductance, and degree of dissociation of the 0.05 M NH₄OH solution.

### Step 1: Calculate Specific Conductance (κ)

The specific conductance (κ) is given by the formula:

\[
\kappa = \frac{L}{R}
...