Find the oxidation number of Fe in `K_4 [ Fe(CN)_6]`

Explanation

To find the oxidation number of Fe in the coordination compound \( K_4[Fe(CN)_6] \), we can follow these steps:

### Step 1: Identify the charges of the components
In the compound \( K_4[Fe(CN)_6] \):
- Potassium (K) has a charge of +1. Since there are 4 potassium ions, their total contribution to the charge is \( 4 \times (+1) = +4 \).
- The cyanide ion (CN) has a charge of -1. Since there are 6 cyanide ions, their total contribution to the charge is \( 6 \times (-1) = -6 \).

### Step 2: Set up the equation
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