Experimentally determined magnetic susceptibility results of `(NiCl_4)^(2-)` ion correspond to the presence of two unpaired electrons. Predict the type of hybridization and geometry of this complex.

Explanation

To solve the problem, we need to determine the hybridization and geometry of the complex ion \((NiCl_4)^{2-}\) based on the information given about its magnetic susceptibility, which indicates the presence of two unpaired electrons.

### Step-by-Step Solution:

1. **Determine the Oxidation State of Nickel:**
- The overall charge of the complex \((NiCl_4)^{2-}\) is -2.
- Each chloride ion \((Cl^-)\) has a charge of -1. Since there are four chloride ions, the total contribution from chlorine is \(-4\).
- Let the oxidation state of nickel be \(x\). The equation can be set up as:
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