Predict the number of unpaired electrons in `[Cr(H_2O)_6]^(2+)`

Explanation

To predict the number of unpaired electrons in the complex ion \([Cr(H_2O)_6]^{2+}\), we can follow these steps:

### Step 1: Determine the Oxidation State of Chromium
1. The complex is \([Cr(H_2O)_6]^{2+}\).
2. The oxidation state of chromium (Cr) can be calculated by assuming its oxidation state as \(x\).
3. The water molecules (H2O) are neutral, contributing 0 to the overall charge.
4. The overall charge of the complex is +2. Therefore, we can set up the equation:
\[
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