Octahedral complexes involve the type of hybridization as

Options

A. `sp^3`
B. `dsp^2`
C. `d^2sp^3`
D. `sp^3d`

Explanation

To determine the type of hybridization involved in octahedral complexes, we can follow these steps:

### Step-by-Step Solution:

1. **Definition of Octahedral Complexes**:
- Octahedral complexes are defined as coordination compounds where a central metal atom is surrounded by six ligands. This arrangement leads to an octahedral geometry.

2. **Understanding Hybridization**:
- Hybridization is the concept of mixing atomic orbitals to form new hybrid orbitals that can accommodate the bonding pairs of electrons. In octahedral complexes, we need to find the appropriate hybridization that allows for six orbitals to be involved in bonding.

3. **Counting the Required Orbitals**:
- For octahedral coordination, we need a total of six orbitals. The orbitals that can be used for hybridization are:
- 1 s orbital
- 3 p orbitals
- 2 d orbitals
- This gives us a total of 6 orbitals (1s + 3p + 2d = 6).

4. **Identifying the Hybridization**:
- The hybridization that corresponds to this combination of orbitals is known as **d2sp3** hybridization. This means:
- 2 d orbitals
- 1 s orbital
- 3 p orbitals
- Alternatively, this can also be represented as **sp3d2**, which is the same set of orbitals but arranged differently.

5. **Conclusion**:
- Therefore, the type of hybridization involved in octahedral complexes is **d2sp3** or **sp3d2**.

### Final Answer:
The type of hybridization involved in octahedral complexes is **d2sp3**.