How many moles of AgCl will be precipitated when an excess of `AgNO_3` is added to a molar solution of `[CrCl(H_2O)_5]Cl_2` ?

Explanation

To solve the problem of how many moles of AgCl will be precipitated when an excess of AgNO3 is added to a molar solution of [CrCl(H2O)5]Cl2, we can follow these steps:

### Step 1: Understand the Coordination Compound
The coordination compound given is [CrCl(H2O)5]Cl2. This means that the complex ion is [CrCl(H2O)5]²⁺ and there are 2 Cl⁻ ions associated with it.

### Step 2: Determine the Ionization of the Coordination Compound
When [CrCl(H2O)5]Cl2 is dissolved in water, it dissociates into:
- 1 complex ion: [CrCl(H2O)5]²⁺
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